Metal sulphate (A) xrightarrow{text{Heat}} Ox | vedclass

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Question

(A) The thermal decomposition of ferrous sulphate $(FeSO_4)$ yields ferric oxide $(Fe_2O_3)$,sulphur trioxide $(SO_3)$,and sulphur dioxide $(SO_2)$.$2

Vedclass · Accepted Answer

$FeSO_4, Fe_2O_3, SO_3, SO_2, Na_2CrO_4$

Vedclass · Answer

(A) The thermal decomposition of ferrous sulphate $(FeSO_4)$ yields ferric oxide $(Fe_2O_3)$,sulphur trioxide $(SO_3)$,and sulphur dioxide $(SO_2)$.$2FeSO_{4(s)} \xrightarrow{\Delta} Fe_2O_{3(s)} + SO_{3(g)} + SO_{2(g)}$Here,$(A) = FeSO_4$,$(B) = Fe_2O_3$,$(C) = SO_3$,and $(D) = SO_2$.$SO_2$ gas acts as a reducing agent and reduces dichromate ions $(Cr_2O_7^{2-})$ in acidic medium to green chromium $(III)$ ions $(Cr^{3+})$.$Cr_2O_7^{2-} + 3SO_2 + 2H^+ \rightarrow 2Cr^{3+} + 3SO_4^{2-} + H_2O$When $Na_2O_2$ (a strong oxidizing agent) is added in excess to the green solution containing $Cr^{3+}$,it oxidizes $Cr^{3+}$ to chromate ions $(CrO_4^{2-})$,which form a yellow solution of $Na_2CrO_4$.$2Cr^{3+} + 3Na_2O_2 + 4NaOH \rightarrow 2Na_2CrO_4 + 2Na^+ + 2H_2O$Thus,$(E) = Na_2CrO_4$.

Metal sulphate $(A) \xrightarrow{\text{Heat}}$ Oxide $(B) +$ Gas $(C) +$ Gas $(D) \xrightarrow{Cr_2O_7^{2-} / H^{+}}$ Green solution $\xrightarrow[\text{Excess}]{Na_2O_2}$ Yellow solution $(E)$. Compound $A, B, C, D$ and $E$ are respectively:

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